Réponse:
A.
[tex] \frac{1}{3} + \frac{2}{3} \times \frac{5}{2} + \frac{11}{2} \\ = \frac{1}{3} + \frac{15 + 4}{6} + \frac{11}{2} \\ = \frac{1}{3} + \frac{19}{6} + \frac{11}{2} \\ = \frac{1}{3} \times \frac{11}{2} + \frac{19}{6} \\ = \frac{33 + 2}{6} + \frac{19}{6} \\ = \frac{54}{6} = 9[/tex]
B.
[tex] \frac{ - 1}{6} \times ( \frac{5}{4} - \frac{9}{2} ) \\ = \frac{ - 1}{6} \times ( \frac{5}{4} - \frac{18}{4}) \\ = \frac{ - 1}{6} \times ( \frac{ - 13}{4} ) \\ = \frac{ - 78 - 4}{24} \\ = \frac{ - 82}{24} [/tex]
C.
[tex] \frac{3}{ 5} - \frac{7}{3} \div \frac{2}{7} + 4 \\ \frac{ - 35 + 9}{15} \div \frac{28 + 2}{7} \\ = \frac{ - 26}{15} \div \frac{30}{7} \\ = \frac{ - 26}{15} \times \frac{7}{30} \\ = \frac{ - 182}{450} = \frac{ - 91}{225} [/tex]
