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Sagot :

MCM3

Réponse:

from AB= OB-OA

let M= (x,y)

MA= (7-x)i + (-1-y)j

MB= (-4-x)i + (10-y)j

MC= (-4-x) + (5-y)j

(7-x-4-x-4-x)i + (-1-y+10-y+5-y)j= 0

-1-3x = 0 et 14-3y = 0

x=-1/3 y= 14/3

M(-1/3, 14/3)

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