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Sagot :

CHRYSTINE

bonjour

le trajet vert:

OI²=1²+1²

OI²=2

OI=√2

OI≈1.41m

1÷2=0.5

1.41+0.5=1.91m

trajet rouge:

OJ²=1²+0.5²

OJ²=1+0.25

OJ²=1.25

OJ=√1.25

OJ≈1.12m

JI²=0.5²+0.5²

JI²=0.25+0.25

JI²=0.5

JI=√0.5

JI≈0.71m

1.12+0.71=1.83m

le trajet rouge est plus court

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