b) (x-1)^2 = 2 (x+3)(x-1) équivalent à (x-1)^2 - 2 (x+3)(x-1) = (x - 1)(x - 1 - 2 x - 6) = (x - 1) (-x - 7) = - (x - 1) (x + 7) = 0 , donc x = 1 ou x = -7
c) (x - 1)^2 = - x + 1 = -(x - 1) équivalent à (x - 1)^2 + (x - 1) = (x - 1)(x -1 + 1) = x ( x - 1) = 0 , donc x = 0 ou x = 1 .