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Sagot :

(2x-3)²=9(x+1)²

(2x-3)² - (3(x+1))² = 0

a²-b²=(a+b)(a-b)

((2x-3)+3(x+1)) ((2x-3)-3(x+1))=0

5x*(-x-6)=0

2 solutions ; x=0 ; x=-6

MANI8282

Réponse:

(2x - 3)^2 = 9 * (x + 1)^2

4x^2 - 12x + 9 = 9(x^2 + 2x + 1)

4x^2 - 12x + 9 = 9x^2 + 18x + 9

4x^2 - 12x = 9x^2 + 18x

4x^2 - 12x - 9x^2 - 18x = 0

- 5x^2 - 30x = 0

- 5x x (x + 6) = 0

x(x + 6) = 0

x = 0

x + 6 = 0

X=0

X = -6

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