Sagot :
Bonjour,
a) A = 2(5x+2)(3x+1)
= (10x+4)(3x+1)
= 30x²+10x+12x+4
= 30x²+22x+4
b) (x+2)(3x+2) = 3x²+2x+6x+4 = 3x²+8x+4
donc : B = (x+2)(3x+2)(x+4)
= (3x²+8x+4)(x+4)
= 3x³+12x²+8x²+32x+4x16
= 3x³+20x²+36x+16
c) C = 4(5x-1)(3x+3)
= (20x-4)(3x+3)
= 60x²+60x-12x-12
= 60x²+48x-12
D = (1-x)(1+x)(2x+1)
= (1+x-x-x²)(2x+1)
= (1-x²)(2x+1)
= 2x+1-2x³-x²
Réponse :
Bonjour
Explications étape par étape :
A = 2(5x+2)(3x+1)
A = (10x+4)(3x+1)
A = 30x²+10x +12x +4
A = 30x² + 22x + 4
B = (x+2) (3x+2)
B = 3x²+2x +6x +4
B = 3x²+ 8x+4
ainsi B = (x+2)(3x+2)(x+4)
B = (3x²+8x+4) (x+4)
B = 3x³+12 x² + 8x²+ 32x+ 4x +16
B = 3x³+20x² +36x +16
C = 4 (5x-1)(3x+3)
C = (20x-4) (3x+3)
C = 60x² +60x -12x -12
C = 60x²+ 48x -12
D = (1-x) (1+x)(2x+1)
D = (1+x- x -x²) (2x+1)
D = (1-x²) (2x+1)
D = 2x +1 -2x³ -x²