Sagot :
Bonjour,
Factoriser:
(4x - 9)² - (4x - 9) (2x - 5)= (4x-9)(4x-9-2x+5)= (4x-9)(2x-4)= 2(4x-9)(x-2)
Réponse :
Bonjour,
[tex](4x-9)^2-(4x-9)(2x-5)\\\\= \underline{(4x-9)}(4x-9)-\underline{(4x-9)}(2x-5)\\\\= (4x-9)[(4x-9) - (2x - 5)]\\\\= (4x - 9)(4x - 9 - 2x + 5)\\\\= (4x - 9)(4x - 2x - 9 + 5)\\\\= (4x-9)(2x-4)\\\\= (4x - 9) \times 2(x -2)\\\\= 2(4x-9)(x-2)[/tex]