Bonjour
Résoudre :
(2x - 7)^2 - (x + 2)(2x - 7) = 0
(2x - 7)(2x - 7 - x - 2) = 0
(2x - 7)(x - 9) = 0
2x - 7 = 0 ou x - 9 = 0
2x = 7 ou x = 9
x = 7/2 ou x = 9
6x^2 - x(4x + 2) = 0
x(6x - 4x - 2) = 0
x(2x - 2) = 0
2x(x - 1) = 0
2x = 0 ou x - 1 = 0
x = 0 ou x = 1