Sagot :
bonsoir
Écrire sous forme d’une puissance :
2^3 x 2^5 = 2^(3+5) = 2^8
3^2 x 3 = 3^(2+1) = 3^3
5^4 x 5^2 = 5^(4+2) = 5^6
4^2 x 4^4 = 4^(2+4) = 4^6
3^5/3^2 = 3^(5-2) = 3^3
2^5/2^3 = 2^(5-3) = 2^2
5^4/5^3 = 5^(4-3) = 5^1
7^5/7^2 = 7^(5-2) = 7^3
Réponse:
Exercice 3 :
a )
[tex] {2}^{3} \times {2}^{5} = {2}^{3 + 5} = {2}^{8} [/tex]
b)
[tex] {3}^{2} \times 3 = {3}^{2} \times {3}^{1 } = {3}^{2 + 1} = {3}^{3} [/tex]
c)
[tex] {5}^{4} \times {5}^{2} = {5}^{4 + 2} = {5}^{6} [/tex]
d)
[tex] {4}^{2} \times {4}^{4} = {4}^{2 + 4} = {4}^{6} [/tex]
Exercice 4:
a)
[tex] \frac{ {3}^{5} }{ {3}^{2} } = {3}^{5 - 2} = {5}^{3} [/tex]
b)
[tex] \frac{ {2}^{5} }{ {2}^{3} } = {2}^{5 - 3} = {2}^{2} [/tex]
c)
[tex] \frac{ {5}^{4} }{ {5}^{3} } = {5}^{4 - 3} = {5}^{1} [/tex]
d)
[tex] \frac{ {7}^{5} }{ {7}^{2} } = {7}^{5 - 2} = {7}^{3} [/tex]