bonjour
f (x) = ( 3 x - 5 ) ( 3 x + 5 ) - ( - 2 x + 3 ) ( 3 x - 5 )
f (x) = 9 x² - 25 - ( - 6 x² + 10 x + 9 x- 15 )
f (x) = 9 x² - 25 + 6 x² - 19 x + 15
f (x) = 15 x² - 19 x - 10
f (x) = ( 3 x - 5 ) ( 3 x + 5 + 2 x - 3 )
f (x) = ( 3 x - 5 ) ( 5 x + 2 )
f (x) = 0
( 3 x - 5 ) ( 5 x + 2) = 0 ⇔ x = 5/3 ou - 2/5
f ( √2) = 15 ( √2)² - 19 √2 - 10 = 30 - 19 √2 - 10 = 20 - 19 √2
15 x² - 19 x - 10 = - 10
15 x² - 19 x = 0
x ( 15 x - 19) = 0 ⇔ x = 0 ou 19/15