Réponse:
1)
[tex] {(16x}^{2} - 24x + 9) + ( {24x}^{2} -18x + 4x - 3) [/tex]
[tex]16 {x}^{2} - 24x + 9 + 24 {x}^{2} - 14x - 3[/tex]
[tex]40 {x}^{2} - 38x + 6[/tex]
2)
[tex](4x - 3)((4x - 3) + (6x + 1)) = (4x - 3)(4x + 6x + 1 - 3) = (4x - 3)(10x - 2)[/tex]
3)
[tex]4x - 3 = 0 \\ 4x = 3 \\ x = \frac{3}{4} [/tex]
ou
[tex]10x - 2 = 0 \\ 10x = 2 \\ x = \frac{2}{10} = \frac{1}{5} [/tex]
f(x)=0 pour
[tex] \frac{1}{5} \: et \: \frac{3}{4} [/tex]
[tex]40 {x}^{2} - 38x + 6 = 6 \\ 40 {x}^{2} - 38 x= 0 \\x(40x - 38) = 0 \\ x = 0 \\ ou40x - 38 = 0 \\ 40x = 38 \\ x = \frac{38}{40} = \frac{19}{20} \\ f(x) = 6 \: pour \: 0 \: et \frac{19}{20} [/tex]
