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Sagot :

Réponse:

[tex]4 {x}^{2} - 9 = {(2x)}^{2} - {3 }^{2} \\ = (2x - 3) \times (2x + 3) \\ =0[/tex]

c est a dire ( 2x-3) = 0 ou ( 2x+3) = 0

c est a dire x = 3/2 ou x = - 3/2

bon courage !!!

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