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Sagot :

Réponse :

Explications étape par étape

Bonjour

Factoriser les expressions suivantes:

A= (x+2)(2x+3)-(x+2)(x+1)

A = (x + 2)(2x + 3 - x - 1)

A = (x + 2)(x + 2)

A = (x + 2)^2

B=(2x+1)-(2-x)(2x+1)

B = (2x + 1)(1 - 2 + x)

B = (2x + 1)(x - 1)

C=(x+3)(-x+1)-(x+3)au carré

C = (x + 3)(-x + 1 - x - 3)

C = (x + 3)(-2x - 2)

C = (x + 3) * (-2)(x + 1)

C = (-2)(x + 3)(x + 1)

Réponse :

Bonjour

Explications étape par étape

Factorisation

A = (x+2) (2x+3)- (x+2)(x+1)

A = (x+2) (2x +3 -x -1)

A = (x+2) (x +2) = (x+2)²

B = (2x+1) - (2-x)(2x+1)

B = (2x +1) (-2x +x)

C = (x+3) (-x+1) - (x+3

C = ( x+3) (-x +1 -x -3)

C = (x +3) (-2x -2)

C = (x +3) ( -2)(x +1)

C = (-2) (x +3)(x+1)  

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