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Sagot :

Réponse:

exo15

PPCM (15;20;6)=60

D=[14(4)-7(3)-1(10)]/60

=(56-21-10)60

=(56-31)/60

=25/60

=(25÷5)/(60÷5)

=5/12

PPCM (8;24;12)=24

D=[-5(3)-5-5(2)]/24

=(-15-5-10)/24

= -30/24

=(-30÷6)/(24÷6)

= -5/4

F=11/6-(-3/4-5/6)

=11/6-[(-3×6)-(5×4)]/4×6

=11/6-(-18-20)/24

=11/6-(-38/24)

=11/6+38/24

=(11×4)/(6×4)+38/24

=44/24+38/24

=(44+38)/24

=82/24

=82÷2/24÷2

= 41/12

G=(4/21-3/7)-(3/10-8/15)

=[(4-(3×3))/21-(3×15-8×10)/10×15

=(4-9)/21-(45-80)/150

= -5/21-(-35/150)

= -5/21+35/150

=[(-5×50)+(35×7)]/1050

=(-250+245)/1050

= -5/1050

=( -5÷5)/(1050÷5)

= -1/210

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