Sagot :
Réponse:
exo15
PPCM (15;20;6)=60
D=[14(4)-7(3)-1(10)]/60
=(56-21-10)60
=(56-31)/60
=25/60
=(25÷5)/(60÷5)
=5/12
PPCM (8;24;12)=24
D=[-5(3)-5-5(2)]/24
=(-15-5-10)/24
= -30/24
=(-30÷6)/(24÷6)
= -5/4
F=11/6-(-3/4-5/6)
=11/6-[(-3×6)-(5×4)]/4×6
=11/6-(-18-20)/24
=11/6-(-38/24)
=11/6+38/24
=(11×4)/(6×4)+38/24
=44/24+38/24
=(44+38)/24
=82/24
=82÷2/24÷2
= 41/12
G=(4/21-3/7)-(3/10-8/15)
=[(4-(3×3))/21-(3×15-8×10)/10×15
=(4-9)/21-(45-80)/150
= -5/21-(-35/150)
= -5/21+35/150
=[(-5×50)+(35×7)]/1050
=(-250+245)/1050
= -5/1050
=( -5÷5)/(1050÷5)
= -1/210