1) x=0
(5-2x)(5+2x)
(5-2x0)(5+2x0)
5x5=25 donc ça correspond à b)
2) (2x-3)²=4x²-12x+9
3) (2x-3)(x-5)
2x²-10x-3x+15
2x²-13x+15
A = 19/5-4/5x7/2
= 19/5-28/10
=38/10-28/10=10/10 ou 1
A = 8x(x+2)+(5x-1)(x+7)
=8x²+16x+(5x²+35x-x-7)
= 8x²+16x+5x²+35x-x-7
= 13x²+50x-7
B = (x+5)²-(2x+3)(x-1)
= x²+10x+25-(2x²-2x+3x-3)
= x²+10x+25-2x²+2x-3x+3
= -x²+9x+28