soit D =(2x+3)2 +(2x+3)(7x-2)


Sagot :

soit D =(2x+3)² +(2x+3)(7x-2)
          =(2x+3)(2x+3+7x-2)
          =(2x+3)(9x+1)
D= (2x+3)2+(2x+3)(7x-2)
= (2x+3)[(2x+3)+(7x-2)]
= (2x+3)(2x+3+7x-2)
= (2x+3)(9x+1)