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(Maths repères 2nd éditions hachette) 

 

page 76 n°96 

 

a) (3x - 1)² - (2x +1)²

 

b) (x + 4)² - (2x -6)² 

 

c) (-2x + 3)² - \frac{1}{4}x² 

 

d) 4(x + 2)² - 9(2x - 1)² 

 

 

 

 

Sagot :

a) (9x²-6x+1)-(4x²+4x+1)
   9x²-6x+1-4x²-4x-1
     5x²-10x
b) (x²+8x+16)-(4x²-24x+36)
   x²+8x+16-4x²+24x-36
   -3x²+32x-20
d)4(x²+4x+4)-9(4x²-4x+1)
   4x²+16x+16-36x²+36x-9
   -32x²+52x+7
c) je n'ai pas compris ton énoncé
a) (3x - 1)² - (2x +1)² =9x²-6x+1-(4x²+4x+1)=9x²-6x+1-4x²-4x-1=5x²-10x
b) (x + 4)² - (2x -6)²  =x²+8x+16-(4x²-24x+36)=x²+8x+16-4x²+24x-36= -3x²+32x-20
c) (-2x + 3)² - \frac{1}{4}x²  =4x²-12x+9-[tex] \frac{1}{16} } [/tex]=4x²-12x+[tex] \frac{144-1}{16} [/tex]=4x²-12x+[tex] \frac{143}{16} [/tex]
d) 4(x + 2)² - 9(2x - 1)² =4(x²+4x+4)-9(4x²-4x+1)=4x²+16x+16-36x²+36x-9= -32x²+52x+7

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