a)
[tex] \frac{a+2}{1+b} = -1\\ a+2 = -1 - b\\ a+b = -3[/tex]
[tex]\frac{4a+2}{4+b} = -3\\ 4a+2 = -12-3b\\ 4a+3b=-14[/tex]
[tex]\left \{ {{4a+3b=-14} \atop {3a+3b=-9}} \right.\\ a=-14+9\\ a=-5\\ b=-3+5\\ b=2 [/tex]
b)
[tex]\frac{ax(x-1)+b(x-1)+c}{x-1}\\ \frac{ax^2-ax+bx-b+c}{x-1}\\ en\,comparant : \\ a=1\\ -x+bx=-3x\\ b = -3+1\\ b=-2\\ 2+c=3\\ c=1[/tex]
en espérant t'avoir aidé.
