Bonjour,
-2x²- 4 x + 5 = 2 <--> -2x²-4x+3=0
delta =( -4)²-4*(-2)*3 = 16+24 = 40
Delta est >0 donc il y a deus solutions :
x1 = (4+V40)/-2*2 = (4+V40)/-4 = (4+V4*10)/-4 = (4+2V10)/-4 = -1-(V10)/2
x2 = (4-V40)/-2*2 = (4-V40)/-4 = (4-V4*10)/-4 = (4-2V10)/-4 = -1+(V10)/2
S = {-1-(V10)/2 ; -1+(V10)/2 }
J'espère que tu as compris
a+
