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Sagot :

BAPTMAN

Il faut résoudre 

0.5x²=3x-4

0.5x²-3x+4=0

Delta=9-4*4*0.5=9-8=1

Donc 

x_1=3-1=2

x_2=3+1=4

 

 

 

 

 

 

 

 

 

 

 

 

 

ISAPAUL

f(x) =0.5x²      et g(x) = 3x-4

f(x)= g(x) 

0.5x² - 3x+4 = 0

Delta = (-3)² - 4 ( 0.5 * 4) = 1

deux solutions

x' = (3-1)/1 = 2

x" = (3+1)/1 = 4

 

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