Bonjour
♧ Developper , Réduire & Ordonner :
A(x) = (x-4)(2x+3)
A(x) = x×2x + x×3 - 4×2x - 4×3
A(x) = 2x² + 3x - 8x - 12
A(x) = 2x² - 5x - 12
B(x) = (x-3)²+4(x+1)
B(x) = (x² - 2×x×3 + 3²) + 4×x + 4×1
B(x) = x² - 6x + 9 + 4x + 4
B(x) = x² -6x + 4x + 9 + 4
B(x) = x² -2x + 13
D(x) = (1-2x)²- (x-3)(x+2)
D(x) = ( 1²-2×1×2x+(2x)²) - (x×x + x×2 - 3×x -3×2)
D(x) = 1 - 4x + 4x² - (x² + 2x - 3x - 6)
D(x) = 1 - 4x + 4x² - x² - 2x + 3x + 6
D(x) = 4x² - x² + 3x -4x -2x + 6 + 1
D(x) = 3x² -3x + 7
Voilà ^^
