JUJUAIRE
Answered

a.(-1/4 + 2x)(-2/5-x)

b. (-x-5)(-2x+3)

 

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Sagot :

BENIMOYS
a) =(-1/4)*(-2/5)+(x/4)-(4x/5)-2x^2
=(2/20)+((5x-16x)/20)-2x^2
=-2x^2 -(9x/20)+(1/10)

b) =2x^2 -3x +10x -15
= 2x^2 +7x -15