Bonsoir,
[tex] \frac{ {x}^{4} - 16 }{x - 2} = \frac{x {}^{4} - 2 {}^{4} }{x - 2} = \frac{(x - 2)(x + 2)( {x}^{2} + 4)}{x - 2} = (x + 2)( {x}^{2} + 4)[/tex]
Ainsi on obtient :
[tex]$\lim_{x \to +2} \frac{x {}^{4} - 16 }{x - 2} = (2 + 2)( {2}^{2} + 4) = 4 \times 8 = 32 $[/tex]
CQFD