Sagot :
Bonjour,
Ex2
a = |2 - 3| = |-1| = 1
b = |5 + 3| = |8| = 8
c = |2 × (4 - 5)| = | 2 ×(-1)| = |-2| = 2
d = |4 × 2 - 5 × 7| = |8 - 35| = |-27| = 27
e = |7 + 2| × |4 - 6| = |9| × |-2| = 9 × 2 = 18
f = |2 - 3| × 2 = |-1| × 2 = 1 × 2 = 2
g = |5,5| + |-5,5| = 5,5 + 5,5 = 11
h = |-5,5| - |4,5| = 5,5 - 4,5 = 1
Ex3
a = |2 × 3 - 7| = |6 - 7| = |-1| = 1
b = |√2 - √3| = √3 - √2 car √3 > √2 soit √3 - √2 > 0
c = 2 × |3 × 1/4 - 2| + 1 = 2 × |3/4 - 8/4| + 1 = 2 × |-5/4| + 1 = 2 × 5/4 + 1 = 7/2
d = (|3| + |-3|) / |2 - 1/n| = (3 + 3) / (2 - 1/n) = 6 / (2 - 1/n) ; remplacez n par sa valeur et terminez le calcul.
e = |3 - π| = π - 3 puisque π > 3
f = | 2 × |2 × 5 - 12| - 7| = |2 × |-2| - 7| = |2 × 2 - 7| = |-3| = 3