Sagot :
bonjour
E = 13 - 2 ( x - 5 ) ( x - 1 )
= 13 - 2 ( x² - x - 5 x + 5)
=13 - 2 ( x² - 6 x + 5 )
= 13 - 2 x² + 12 x - 10
= - 2 x² + 12 x + 3
C = (x+2)(x+4)+(x+2)(5x-5)
= ( x + 2) ( x + 4 + 5 x - 5 )
= ( x + 2 ) ( 6 x - 1 )
D= (x+1)(3x-5)-(x+1)(4x+5)
= ( x + 1 ) ( 3 x - 5 - 4 x - 5)
= ( x + 1 ) ( - x - 10 )
Réponse :
bonjour
Explications étape par étape :
E= 13-2 ( x-5) (x-1)
=13-(2x-10)(x-1)
=13-[2x²-2x-10x+10)
=13-2x²+2x+10x-10
=-2x²+12x+3
C= (x+2)(x+4)+(x+2)(5x-5)
=(x+2) (x+4+5x-5)
=(x+2) (6x-1)
D= (x+1)(3x-5)-(x+1)(4x+5)
=(x+1) (3x-5-4x-5)
=(x+1)(-x-10)