Bonjour
Ecrire sous forme canonique= a(x-α)² + β
B(x)= x²+8x+3
B(x)= (x²+2(4x)+4²)-4²+3
B= (x+4)²-4²+3
B(x)= (x+4)²-16+3
B(x)= (x+4)² - 13
C(x)= x²-10x+9
C(x)= x²- 2(5x)+ 9
C(x)= (x²- 2(5)x+ 5²) -5²+9(
C(x) = (x-5)²-5²+9
C(x)= (x-5)² - 25+9
C(x)= (x-5)² - 16
D(x) = x²+2x+7
D(x)= x²+2(x)+1-1+7
D(x)= (x+1)²-1+7
D(x)= (x+1)²+6
E(x)= x²-5x-1
E(x)= x²-2(5x/2)+5/2²-1
E(x)= (x-5/2)²- 25/4 - 1
E(x)= (x-5/2)²- (25/4)-4(4))
E(x)= (x-5/2)²- 29/4
F(x)= x²+7x+3
F(x)= x²+2(7x/2)+(7/2)²-(7/2)²+3
F(x)= (x+7/2)²-(7/2)²+3
F(x)= (x+7/2)²-49/4 + 3
F(x)= (x+7/2)²-49/4 + (3*4)/4
F(x)= (x+7/2)²-37/4
G(x)= 2x²-12x+8
G(x)= 2(x²-6x)+8
G(x)= 2(x²-2(3x)+3²-3²)+8
G(x)= 2((x-3)²-9) + 8
G(x)= 2(x-3)²-18+8
G(x)= 2(x-3)²-10
H(x)= 3x²+15x-7
H(x)= 3(x²-5x)-7
même raisonnement que la G(x)
donc H(x)= 3(x+5/2)²-103/4
