Sagot :
1) v = d/t ⇔ d = t×
d = 210 × 30/60²
d = 1,75 km
2) Sin(ASH) = AH/AS
⇔ AH = AS × sin(ASH)
⇔ AH = 1,75 × sin(40)
⇔ AH ≈ 1,12
d = 210 × 30/60²
d = 1,75 km
2) Sin(ASH) = AH/AS
⇔ AH = AS × sin(ASH)
⇔ AH = 1,75 × sin(40)
⇔ AH ≈ 1,12
Explications étape par étape :
V = 210 km/h
210 km → 3600 s
En 30 s:
( 30 * 210 ) / 3600 = 1,75 km 1h = 3600 s
Distance parcourue : 1,75 km
sin40 = AH / 1,75
⇔ AH = 1,75 sin40
⇔ AH ≅ 1,125 km