Réponse :
Explications étape par étape :
■ sin(100t - 5π/6) = 0 donne
100t - 5π/6 = 0 + 2kπ OU 100t - 5π/6 = π + 2kπ
100t = 5π/6 + 2kπ 100t = 11π/6 + 2kπ
t = π/120 + kπ/50 t = 11π/600 + kπ/50
■ Solution = { π/120 + kπ/100 } avec k entier relatif .
■ vérif :
t --> π/120 11π/600 17π/600 23π/600 29π/600
100t--> 5π/6 11π/6 17π/6 23π/6 29π/6
1oot-5π/6 -> 0 π 2π 3π 4π
sinus --> 0 0 0 0 0
