1) f’(✘) = 0
2)f’(✘) = 1 + 0 = 1
3)f’(✘) = 0 - 3×1 = -3
4)f’(✘) = -3✘² + 5×1 - 0 = -3✘²+5
5) f(✘) = (3✘-1)(2✘+7)
u = 3✘-1
u’ = 3
v = 2✘+7
v’ = 2
f’(✘) = 3(2✘+7)+ (3✘-1)2
f’(✘) = 6✘ + 21 + 6✘ -2
f’(✘) = 12✘ + 19
6) f(✘) = 8✘-7/3
f(✘) = 8✘-7 × 1/3
f’(✘) = 8 × 1/3
f’(✘) = 8/3