8 x a + 8 x 1 = 8 (a+1)
3 x 4 + g x 4 = 4 (3+g)
3b - 3c = 3(b-c)
a x 5 + b x a = a(5+b)
5 x t + 8 x t ² = t (5+8t)
Bonjour,
1. Factoriser les expressions littérales suivantes :
KA + KB = K(A + B)
A = 8a + 8 * 1
A = 8a + 8
A = 8(a + 1)
B = 3 * 4 + 4g
B = 12 + 4g
B = 4(3 + g)
C = 3b - 3c
C = 3(b - c)
D = 5a + ba
D = a(5 + b)
E = 5t + 8t²
E = t(5 + 8t)
Bonne journée.
