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x(-4x+3)+1=0
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Sagot :

( -4 + 3) + 1 = 0

-4² + 3x + 1 = 0

Δ = b² - 4ac
= 3² - 4 x (-4) x 1
= 25
Δ > 0 donc on a deux solutions :

₁= -b-√Δ / 2a
= -3-√25/ 2x(-4)
= 1

₂= -b+√Δ / 2a
= -3+√25/2x(-4)
= -1/4

S= {-1/4 ; 1}