Bonjour,
1) Cu(NO₃)₂(s) → Cu²⁺(aq) + 2NO₃⁻(aq)
2) m = 10,5 g
M(Cu(NO₃)₂) = M(Cu) + 2xM(N) + 6xM(O) = 63,5 + 2x14,0 + 6x16,0 = 187,5 g.mol⁻¹
⇒ n(Cu(NO₃)₂) = m/M(Cu(NO₃)₂) = 10,5/187,5 = 5,6.10⁻² mol
⇒ C = n(Cu(NO₃)₂)/v = 5,6.10⁻²/150.10⁻³ ≈ 0,37 mol.L⁻¹
3)
Cu(NO₃)₂ → Cu²⁺ + 2NO₃⁻
Etat Avanct
initial 0 5,6.10⁻² 0 0
en cours x 5,6.10⁻² - x x 2x
final xf 5,6.10⁻² - xf xf 2xf
⇒ xf = 5,6.10⁻² mol
⇒ [Cu²⁺] = xf/v et [NO₃⁻] = 2xf/v
4) [Cu²⁺] = xf/v = C et [NO₃⁻] = 2xf/v = 2C