Sagot :
Bonsoir, oui, tu as juste!
(2x-1)^2-(3x-1)(2x+3)
4x^2-4x+1-(6x^2+9x-2x-3)
4x^2-4x+1-(6x^2+7x-3)
4x^2-4x+1-6x^2+7x+3
=-3x^2-11x+4
(2x-1)^2-(3x-1)(2x+3)
4x^2-4x+1-(6x^2+9x-2x-3)
4x^2-4x+1-(6x^2+7x-3)
4x^2-4x+1-6x^2+7x+3
=-3x^2-11x+4
Réponse:
oui tu as bon normalement
Explications étape par étape:
= (2x - 1)² - (3x - 1) × (2x+3)
= 4x² - 4x + 1 - (6x² + 9x - 2x - 3)
= 4x² - 4x + 1 - (6x² + 7x - 3)
= 4x2 - 4x + 1 - 6x² + 7x + 3
= -2x² - 11x + 4