Bonjour
3(2 - x) < 2(7 - 3x)
6 - 3x < 14 - 6x
6x - 3x < 14 - 6
3x < 8
x < 8/3
x € ]-inf ; 8/3[
-x << 1 - 5x
5x - x << 1
4x << 1
x << 1/4
x € ]-inf ; 1/4]