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bonjour

( x - 3 ) ( x + 5 ) = 0

équation produit nul

x = 3 ou - 5

x² + 6 x + 9 = 0

( x + 3 )² = 0

x = - 3

x² - 7 = 0

x ² = 7

x = √7 ou - √ 7

x² = 0

x = 0

x² + 9 = 0

x² = - 9

pas de solution dans R

x² + 6 x + 9 - 4 = 0

x² + 6 x + 5 = 0

( x + 5 ) ( x + 2 ) = 0

x = - 5 ou - 2

x² - 8 x - 20 = 0

( x + 2 ) ( x - 10 ) = 0

x = - 2 ou 10

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