Bonjour
Développer et réduire :
2(x+1) = 2x + 2
-4(2-x) = - 8 + 4x
(x+3) + (x+5) = x + 3 + x + 5 = 2x + 8
(x+4)(x-4) = x² - 16
(5-2x) (2x+5) = 10x + 25 - 4x² - 10x = - 4x² + 25
Factoriser
2x+4 = 2 (x + 2)
9x-9 = 9 (x - 1)
3x² +7x = x (3x + 7)
(x+4) (2x+2)+(x+4) (
x-1) = (x + 4) (2x + 2 + x - 1) = (x + 4) (3x + 1)
9x²-64 = (3x - 8) (3x + 8).
