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Calcule en respectant les priorités opératoires
1/2 - 3/4 x 16/9 = ?
(1/2 - 3/4) x 16/9
1/5 - 3/10 x 1/6 + 1/2
(1/5 - 3/10) x (1/6 + 1/2)
Je tiens a préciser que / c'est la barre de fraction
Svp aidez moi et mettez les étapes et la réponse
Merci

Sagot :

Bonjour

Calcule en respectant les priorités opératoires

1/2 - 3/4 x 16/9

= 1/2 - 48/54

= (1 x 27) / (2 x 27) - 48/54

= 27/54 - 48/54

= - 21/54

= (3 x - 7) / (3 x 18)

= - 7/18

(1/2 - 3/4) x 16/9

= [(1 x 2) / (2 x 2) - 3/4] x 16/9

= (2/4 - 3/4)  x 16/9

= - 1/4 x 16/9

= - 16/36

= (4 x - 4) / (4 x 9)

= - 4/9

1/5 - 3/10 x 1/6 + 1/2

= 1/5 - 3/60 + 1/2

= (1 x 12) / (5 x 12) - 3/60 + (1 x 15) / (2 x 15)

= 12/60 - 3/60 + 15/60

= 27/60 - 3/60

= 24/60

= (12 x 2) / (12 x 5)

= 2/5

(1/5 - 3/10) x (1/6 + 1/2)

= [(1 x 2) / (5 x 2) - 3/10] x [1/6 + (1 x 3) / (2 x 3)]

= (2/10 - 3/10) x (1/6 + 3/6)

= - 1/10 x 4/6

= - 4/60

= (4 x - 1) / (4 x 15)

= - 1/15.

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