Sagot :
Bonjour,
4x² +9-8+7x²-9x+12
= 11x² -9x +13
5x(3x+3)-2x(6x-7)
= 15x² +15x -(12x² +14x)
= 15x² +15x -12x² -14x
= 3x²+x
choisis -9 ajoute 5 multiplie par 2 soustrais 5
-9
-9+5 = -4
-4*2 = -8
-8-5 = -13
(6x+3)(7x-3)
= 42x² -18x+21x -9
= 42x² +3x -9
5x+3=2x+6
5x-2x = 6 -3
3x= 3
3/3
=1
(3x+6)(4x-4)=0
Soit
3x+6 = 0
3x=-6
x= -6/3
x= -2
soit
4x-4 = 0
4x= 4
x= 4/4
x= 1
1/ 4x carré +7x carré -9x-9-8+12 = 11x carré -9x-5
2/ 5x(3x+3)-2x(6x-7) = 3x carre + 29x
3/ -9+5(2)-5 = -4
4/ (6x+3) (7x-3) =42x carre +3x-9
5/ 5x+3 =2x+6
=1
6/ (3x+6) (4x-4) =0
= 12x carre +12x-24 =0
Discriminant = b carré -4ac
= (12) carré - 4(12)(-24)
=144-1152
= -1008
Discriminant < 0 alors solution ensemble vide
J’espère t’avoir aider
2/ 5x(3x+3)-2x(6x-7) = 3x carre + 29x
3/ -9+5(2)-5 = -4
4/ (6x+3) (7x-3) =42x carre +3x-9
5/ 5x+3 =2x+6
=1
6/ (3x+6) (4x-4) =0
= 12x carre +12x-24 =0
Discriminant = b carré -4ac
= (12) carré - 4(12)(-24)
=144-1152
= -1008
Discriminant < 0 alors solution ensemble vide
J’espère t’avoir aider