bonjour
P (x) = 4 x² - x - 3
P (x) = 0
4 x² - x - 3 = 0
Δ = 1 - 4 ( 4 x - 3 ) = 1 + 48 = 49 ( = 7²)
x 1 = ( 1 - 7 ) / 8 = - 6 /8 = - 3 /4
x 2 = ( 1 + 7 ) /8 = 8/8 = 1
donc S { - 3/4 ; 1 }
je te montre le premier pour la suite
4 x⁴ - x² - 3 = 0
4 X² - x - 3 = 0
Δ = 1 - 4 ( 4 * - 3 ) = 1 + 48 = 49
x 1 = ( 1 - 7 ) / 8 = - 6 /8 = - 3/4
x 2 = ( 1 + 7 ) / 8 = 1
x ² = 3/4 ⇔ x = √3/4 ou - √ 3/4
x² = 1 ⇔ x = √1 ou - √1
S { - √3/4 ; √3/4 ; - √1 ; √ 1 }
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