Réponse:
1°) en utilisant la règle distributivité simple calculer :
A= 2x (3x-7)
A = 6x-14
B= -5(X² +2X +3)
B = 5X² +10X +15
C= X(-4X-5)
C= -4X²-5X
D= -2X(6X+4)
D= -12X²-8X
E= 6(3-3X+2x²)
E = 18-18X +12X²
2) en utilisant la règle de distributivité, calculer :
I= (2X-7)(5X+2)
= 2X( 5X+2)-7(5X+2)
= 10X² +4X-35X-14
I = 10X²-31X-14
J=(4X+1)(3X+8)
= 4X(3X+8) + 1(3X+8)
=12X² +32X +3X + 24
J = 12X² +35X +24
K= (5X+5)(X+2)
= 5X(X+2) + 5(X+2)
= 10X² +10X +10X +10
K= 10X² +20X +10
L=(2X-1) (X+5)
=2X(X+5) -1( X+5)
= 10X² +10 X -X -5
L= 10X² +9X -5
exercice 4:
écrire sous forme factorisée :
A =5 (X-2) + 2X (X-2)
A = (X-2)(5+2X)
B=( X-4) (3X+4) + 5(X-4)
= (X-4) ( 3X+4 +5)
B= (X-4) ( 3X +9)
C=(3X+1)² - 4( 3X+1)
=(3X+1) (3X+1) - 4 (3X+1)
= (3X+1)( 3X+1 -4)
C = (3X+1 ) ( 3X -3)
bonne fin de soirée ☺️
