bonjour
f (1) = 4 et f ( 3) = 10
( 10 - 4 ) : ( 3 - 1 ) = 6 /2 = 3
ax = 3 x
f (1) = 4
1 * 3 + b = 4
b = 4 - 3 = 1
f (x) = 3 x + 1
d'où f ( 3 ) = 3 * 3 + 1 = 10
g (- 1 ) = 5 et g ( 1 ) = 1
( 1 - 5 ) : ( 1 + 1 ) = - 4 /2 = - 2
ax = - 2 x
g ( -1 ) = 5
- 1 * - 2 + b = 5
b = 5 - 2 = 3
g (x) = - 2 x + 3
d'où g ( 1 ) = 1 * - 2 + 3 = - 2 + 3 = 1
fais pareil pour h , tu verras si tu as compris