Sagot :
bonjour
z = 5(x + 1) + 3(x+1)
z = ( x + 1 ) ( 5 + 3 ) = 8 ( x + 1 )
A = 13(x + 2) + 5(x + 2)
A = ( x + 2 ) ( 13 + 5 ) = 18 ( x + 2 )
B = 7(2x - 3) + 2(2x - 3)
B = ( 2 x - 3 ) ( 7 + 2 ) = 9 ( 2 x - 3 )
Z = (x + 1)(5+3) est déjà factorisé
Z = 8(x + 1) déjà factorisé
C = 3x(x + 2) -5(x + 2)
C = ( x + 2 ) ( 3 x - 5 )
D = 4(x + 3) + 9x(x + 3)
D = ( x + 3 ) ( 4 + 9 x )
E = 7x(3x + 1) - 10x(3x + 1)
E = ( 3 x + 1 ) ( 7 x - 10 x = - 3 x ( 3 x + 1 )
Réponse:
z = 5(x + 1) + 3(x+1) = (5+3) ( x+1)= 8(x+1)
A = 13(x + 2) + 5(x + 2)= (13+5)(x+2)= 18(x+2)
B = 7(2x - 3) + 2(2x - 3)=(7+2)(2x-3)=9(2x-3)
Z = (x + 1)(5+3)= 8(x + 1)
C = 3x(x + 2) -5(x + 2) = (3x-5)(x+2)
D = 4(x + 3) + 9x(x + 3)= (4+9x)(x+3)
E = 7x(3x + 1) - 10x(3x + 1) =(7x-10x)(3x+1)= -3x(3x+1)