👤

Sagot :

Bonjour,

5b+25 = 5(b+5)

3x²+x = x(3x+1)

8t²+2t = 2t(4t+1)

-x+3x² = x(-1+3x)

3y²+9y² = y²(3+9) = 12y²

9x²-4 = (3x)²-2² = (3x-2)(3x+2)

36x²-25 = (6x)²-5² = (6x-5)(6x+5)

(2x-3)(x+2)-5(2x-3) = (2x-3)(x+2-5) = (2x-3)(x-3)

(5x+1)(3x-5)-(x-3)(5x+1) = (5x+1)((3x-5)-(x-3)) = (5x+1)(2x-2) = 2(5x+1)(x-1)

(2x-3)²-(x+2)² = ((2x-3)+(x+2))((2x-3)-(x+2)) = (3x-1)(x-5)

SELIMANEB7759

Réponse :

Explications étape par étape :

A = 5b + 25 = 5 (b+ 5)

B = 3 x² + x= x ( 3 x + 1)

C =  8 t² + 2 t = 2t (4t + 1)

D = - x + 3x² = x ( -1 + 3x)

E  = 3 y² + 9 y² = 12 y²

F = 9x ² - 4= (3x - 2) ( 3x + 2)

G = 36x² - 25 = (6x - 5)(6x +5)

a (2x -3) (x+2) - 5 (2x -3) = (2x -3) ( x +2 -5) = (2x -3) ( x-3)

b (5x +1 ) (3x -5) - (x - 3) (5x +1) = (5x +1 ) ( 3x -5 -(x -3))= (5x +1= (3x -5 -x +3)

                                                                                        = (5x +1 ) (2x + 2)

c (2x -3 )² - (x+2)² = (2x-3 - (x+2)) (2x-3 +x -2) = (2x -3 -x-2) (3x - 5)

                                                                          = (x - 5)(3x -5)

Other Questions

© 2024 IDNLearn. All rights reserved.