Sagot :
Bonjour,
1) (3x-5)² - (3x-5)(2x+3)
= 9x²-30x+25-(6x²+9x-10x-15)
= 9x²-6x²-30x-9x+10x+25+15
= 3x²-29x+40
2) (3x-5)² - (3x-5)(2x+3)
= (3x-5)(3x-5)-(3x-5)(2x+3)
= (3x-5)[(3x-5)-(2x+3)]
= (3x-5)(x-8)
3) x=-2 ⇒ (3x-5)(x-8) = (3(-2)-5)(-2-8) = (-11)(-10) = 110
Réponse :
bonjour,
C = (3x - 5 )² - (3x - 5) ( 2x+3)
= ( 3x - 5 )( 3x - 5 ) - ( 3x - 5 )( 2x + 3 )
= 9x² - 15x - 15x + 25 -( 6x² + 9x - 10x - 15)
= 9x² - 30x + 25 -6x² - 9x + 10x + 15
= 3x² - 29x + 40
C = C = (3x - 5 )² - (3x - 5) ( 2x+3)
= ( 3x - 5 )( 3x - 5 ) - ( 3x - 5 )( 2x + 3 )
= (3x - 5 ) ( 3x - 5 -(2x + 3) )
= ( 3x - 5 ) ( 3x - 5 - 2x - 3 )
= ( 3x - 5 ) ( x - 8 )
avec x = -2 :
on remplace x par -2
C = 3x² - 29x + 40
= 3 × (-2)² - 29 × (-2) + 40
= 3× 4 - (-58) + 40
= 12 + 58 + 40
= 110
voila:)