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Sagot :

Bonjour,

1) (3x-5)² - (3x-5)(2x+3)

= 9x²-30x+25-(6x²+9x-10x-15)

= 9x²-6x²-30x-9x+10x+25+15

= 3x²-29x+40

2)  (3x-5)² - (3x-5)(2x+3)

= (3x-5)(3x-5)-(3x-5)(2x+3)

= (3x-5)[(3x-5)-(2x+3)]

= (3x-5)(x-8)

3) x=-2 ⇒ (3x-5)(x-8) = (3(-2)-5)(-2-8) = (-11)(-10) = 110

NBA10

Réponse :

bonjour,

C = (3x - 5 )² - (3x - 5) ( 2x+3)

= ( 3x - 5 )( 3x - 5 ) - ( 3x - 5 )( 2x + 3 )

= 9x² - 15x - 15x + 25 -( 6x² + 9x - 10x - 15)

= 9x² - 30x + 25 -6x² - 9x + 10x + 15

= 3x² - 29x + 40

C = C = (3x - 5 )² - (3x - 5) ( 2x+3)

= ( 3x - 5 )( 3x - 5 ) - ( 3x - 5 )( 2x + 3 )

= (3x - 5 ) ( 3x - 5 -(2x + 3) )

= ( 3x - 5 ) ( 3x - 5 - 2x - 3 )

= ( 3x - 5 ) ( x - 8 )

avec x = -2 :

on remplace x par -2

C = 3x² - 29x + 40

= 3 × (-2)² - 29 × (-2) + 40

= 3× 4 - (-58) + 40

= 12 + 58 + 40

= 110

voila:)

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