Bonjour,
ex_2:
[tex]x^2+y^2-6x+2y+5=0\\\\x^2-6x+9+y^2+2y+1+5-10=0\\\\(x-3)^2+(y+1)^2=5\\[/tex]
M appartient au cercle de centre (3;-1) et de rayon √5.
ex_1:
1a)
[tex]f(x)=10-\dfrac{e^{0.2*x+1}}{x} \\\\f'(x)=-\dfrac{e^{0.2*x+1} }{x} *(0.2*x-1)[/tex]
1b)
[tex]\begin{array}{c|cccccc}x&&0&&5&&\\f'(x)&+&||&+&0&-\\f(x)&\nearrow&||&\nearrow&max&\searrow&\searrow\\\end{array}[/tex]
2. x=5 et f(x)=10-e^²/5=8.522188780...
