Réponse:
[tex]a. \frac{1}{9 \times 9} = \frac{1}{ {9}^{2} } = {9}^{ - 2} \\ b. \frac{1}{7 \times 7 \times 7} = \frac{1}{ {7}^{3} } = {7}^{ - 3} \\ c. \frac{1}{3 \times 3 \times 3 \times 3} = \frac{1}{ {3}^{4} } = {3}^{ - 4} \\ d. \frac{1}{6 \times 6 \times 6 \times 6 \times 6} = \frac{1}{ {6}^{5} } = {6}^{ - 5} [/tex]