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Sagot :

BISCOTTE8

Réponse :

1 er exercice

ax2−6ax=0

(a)⋅x2+(−6a)⋅x=0

x⋅[(a)⋅x+(−6a)]=0

x1=0

(a)⋅x2+(−6a)=0

x2=−(−6a)a,a≠0

x2=−(a)

⋅(−6)(a)=6

2nd exercice

−2bx⋅(3x+1)=0

−6bx2−2bx=0

(−6b)⋅x2+(−2b)⋅x=0

x⋅[(−6b)⋅x+(−2b)]=0

x1=0

(−6b)⋅x2+(−2b)=0

x2=−(−2b)−6b,−6b≠0

x2=−(2b)

⋅(−1)(2b)⋅(−3)=−13

3eme exercice

2cx+3c=0

(2c)⋅x+(3c)=0

x=−(3c)2c,2c≠0

x=−(c)

⋅(3)(c)⋅(2)=−32

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