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JUSTME22
Answered

Bonsoir tout lmonde j'aurai besoin d'aide svp merci d'avance
Factoriser les expressions suivantes :


[tex]A=13(x+2)-5(x + 2)[/tex]
[tex]B = 3x(x + 2) - 5(x + 2)[/tex]
[tex]C=(x+3)[/tex]
[tex]D=x ^{2} - 4[/tex]
[tex]E=16-9x {}^{2} [/tex]
[tex]F=(2x+3)(5x-12)+(2x+3)[/tex]
[tex]G=x ^{2} -4x[/tex]
[tex]H=9x ^{2} +24x+16[/tex]
[tex]I=(2x+3)(5x-12)-(2x+3)(4-x)[/tex]
[tex]J=x ^{2} +x(3+5x)[/tex]
[tex]K=x ^{2} -10x+25[/tex]

​

Sagot :

THOMAS756

Bonjour,

A = 13(x + 2) - 5(x + 2)

A = 8(x + 2)

B= 3x(x + 2) - 5(x + 2)

B = (x + 2)(3x - 5)

C déjà factorisé

D = x² - 4

D = x² - 2²

D = (x - 2)(x + 2) #a² - b² = (a - b)(a + b)

E = 16 - 9x²

E = 4² - (3x)²

E = (4 - 3x)(4 + 3x)

F = (2x + 3)(5x - 12) + (2x + 3)

F = (2x + 3)(5x - 12 + 1)

F = (2x + 3)(5x - 11)

G = x² - 4x

G = x(x - 4)

H = 9x² + 24x + 16

H = (3x)² + 2 * 3x * 4 + 4²

H = (3x +4)² #(a + b)² = a² + 2ab + b²

I = (2x + 3)(5x - 12) - (2x + 3)(4 - x)

I = (2x + 3)(5x - 12 - 4 + x)

I = (2x + 3)(6x - 16)

I = (2x + 3)(2*3x - 2*8)

I = 2(2x + 3)(3x - 8)

J = x² + x(3 + 5x)

J = x(x + 3 + 5x)

J = x(6x + 3)

J = 3x(2x + 1)

K = x² - 10x + 25

K = x² - 2 * x * 5 + 5²

K = (x - 5)² #(a - b)² = a² - 2ab + b²

VINS

Réponse :

bonjour

A = ( x + 2 ) ( 13 - 5 ) = 8 ( x + 2 )

B = ( x + 2 ) ( 3 x - 5 )

C =  ?

d = ( x - 2 ) ( x + 2 )

E =  ( 4 - 3 x ) ( 4 + 3 x  )

F = ( 2 x + 3 ) ( 5 x - 12 + 1 )

f = ( 2 x + 3 ) ( 5 x - 11 )

G =  x  ( x - 4 )

H = ( 3 x + 4 )²

i =  ( 2 x + 3 ) ( 5 x - 12 - 4 + x )

I = ( 2 x + 3 ) ( 6 x - 16 )

i =  2( 2 x + 3 ) ( 3 x - 8 )

J =  x² + 3 x + 15 x  = x ( x + 3 + 15) = x ( x + 18)

K  = (x - 5 )²  

Explications étape par étape :

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