Sagot :
(3 - x) (2x + 1) c'est (double distrib) 6x-2x^2+3-x
et donc g(x) vaut 1-5x+2x^2
g(2V3)=1-10V3+24=25-10V3
Bonsoir
g(x) = 4 - (3-x)(2x+1)
g(x) = 4 - (6x+3-2x²-x)
g(x) = 2x²-5x+1
g(2V3) = 2(2V3)² -5(2V3) + 1
g(2V3) = 24 - 10V3 +1
g(2V3) = 25 - 10V3