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Sagot :

1000SOURISVERTE25

f(x)=g(x)

6x²-30x-36=10x-100

6x²-40x+64=0

Δ=b²-4ac=(-40)²-4*6*64=64

64>0 -> 2 solutions

x1=[-b-racine(Δ)]/2a = [40-racine(64)]/2*6 = 8/3

x2=[-b+racine(Δ)]/2a = 4

f(x)=g(x) quand x est égal à 8/3 ou 4.

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